3w^2-26w-77=0

Solution for 3w^2-26w-77=0 equation:

3w^2-26w-77=0

a = 3; b = -26; c = -77;
Δ = b2-4ac
Δ = -262-4·3·(-77)
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-40}{2*3}=\frac{-14}{6}
=-2+1/3
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+40}{2*3}=\frac{66}{6}
=11
$